(1/(h^2+13h))-(1/(13h))

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Solution for (1/(h^2+13h))-(1/(13h)) equation: 


D( h )

h^2+13*h = 0

13*h = 0

h^2+13*h = 0

h^2+13*h = 0

h^2+13*h = 0

DELTA = 13^2-(0*1*4)

DELTA = 169

DELTA > 0

h = (169^(1/2)-13)/(1*2) or h = (-169^(1/2)-13)/(1*2)

h = 0 or h = -13

13*h = 0

13*h = 0

13*h = 0 // : 13

h = 0

h in (-oo:-13) U (-13:0) U (0:+oo)

1/(h^2+13*h)-(1/(13*h)) = 0

1/(h^2+13*h)+(-1/13)*h^-1 = 0

1/(h^2+13*h)-1/(13*h) = 0

h^2+13*h = 0

h^2+13*h = 0

h*(h+13) = 0

h+13 = 0 // - 13

h = -13

h*(h+13) = 0

1/(h*(h+13))-1/(13*h) = 0

(1*13*h)/(13*h*h*(h+13))+(-1*h*(h+13))/(13*h*h*(h+13)) = 0

1*13*h-1*h*(h+13) = 0

-h^2 = 0

(-h^2)/(13*h*h*(h+13)) = 0

(-h^2)/(13*h*h*(h+13)) = 0 // * 13*h*h*(h+13)

-h^2 = 0

-1*h^2 = 0 // : -1

h^2 = 0

h = 0

h in { 0} 

h belongs to the empty set

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